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A FREE SUBGROUP OF THE FREE ABELIAN TOPOLOGICAL GROUP ON THE UNIT INTERVAL ELI KATZ, SIDNEY A. MORRIS AND PETER NICKOLAS §1. Introduction We prove that the free abelian topological group, FA[0,1], on the closed interval [0,1 ] has a closed subgroup topologically isomorphic to FA(0,1), the free abelian topological group on the open interval (0,1). The analogue of this result for the free (non-abelian) topological group F[0,1], was proved by Nickolas [4], but his techniques rely heavily on non-commutativity and cannot be used here. (Note that in neither the abelian nor the non-abelian case does the obvious copy of (0,1) generate the desired subgroup. Moreover, any copy which does must be closed in FA[0,1] or F[0,1], respectively (see [1,3]).) Furthermore, Nickolas's proof does not easily yield an explicit embedding of F(0,1) in F[0,1]. Our proof, on the other hand, is constructive and thus does yield an explicit embedding of FA{0,1) in FA[0,1]—and indeed the analogous construction explicitly embeds F(0,1) in F[0,1] . §2. The main result We first record the necessary definitions and background results. These results are stated in the form we need rather than in their finest versions. A Hausdorff topological space X is said to
Bulletin of the London Mathematical Society – Wiley
Published: Sep 1, 1982
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