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Ground State Solutions for Kirchhoff–Schrödinger–Poisson System with Sign-Changing Potentials

Ground State Solutions for Kirchhoff–Schrödinger–Poisson System with Sign-Changing Potentials In this article, we study the following Kirchhoff–Schrödinger–Poisson system with pure power nonlinearity -(a+b∫R3|∇u|2dx)Δu+V(x)u+K(x)ϕu=h(x)|u|p-1u,x∈R3,-Δϕ=K(x)u2,x∈R3,\documentclass[12pt]{minimal}\usepackage{amsmath}\usepackage{wasysym}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{amsbsy}\usepackage{mathrsfs}\usepackage{upgreek}\setlength{\oddsidemargin}{-69pt}\begin{document}$$\begin{aligned} \left\{ \begin{array}{ll} -\Bigl (a+b \displaystyle \int _{\mathbb {R}^3}|\nabla u|^2{\text {d}}x\Bigr )\Delta u+V(x) u+K(x) \phi u= h(x)|u|^{p-1}u, &{}x\in \mathbb {R}^3, \\ -\Delta \phi =K(x)u^2, &{}x\in \mathbb {R}^3, \end{array} \right. \end{aligned}$$\end{document}where a, b are positive constants, and 3<p<5\documentclass[12pt]{minimal}\usepackage{amsmath}\usepackage{wasysym}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{amsbsy}\usepackage{mathrsfs}\usepackage{upgreek}\setlength{\oddsidemargin}{-69pt}\begin{document}$$3<p<5$$\end{document}. Under some proper assumptions on the potentials V, K and h, not requiring nonnegative property, we find a ground state solution for the above problem with the help of Nehari manifold. http://www.deepdyve.com/assets/images/DeepDyve-Logo-lg.png Bulletin of the Malaysian Mathematical Sciences Society Springer Journals

Ground State Solutions for Kirchhoff–Schrödinger–Poisson System with Sign-Changing Potentials

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References (36)

Publisher
Springer Journals
Copyright
Copyright © Malaysian Mathematical Sciences Society and Penerbit Universiti Sains Malaysia 2021
ISSN
0126-6705
eISSN
2180-4206
DOI
10.1007/s40840-020-01061-z
Publisher site
See Article on Publisher Site

Abstract

In this article, we study the following Kirchhoff–Schrödinger–Poisson system with pure power nonlinearity -(a+b∫R3|∇u|2dx)Δu+V(x)u+K(x)ϕu=h(x)|u|p-1u,x∈R3,-Δϕ=K(x)u2,x∈R3,\documentclass[12pt]{minimal}\usepackage{amsmath}\usepackage{wasysym}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{amsbsy}\usepackage{mathrsfs}\usepackage{upgreek}\setlength{\oddsidemargin}{-69pt}\begin{document}$$\begin{aligned} \left\{ \begin{array}{ll} -\Bigl (a+b \displaystyle \int _{\mathbb {R}^3}|\nabla u|^2{\text {d}}x\Bigr )\Delta u+V(x) u+K(x) \phi u= h(x)|u|^{p-1}u, &{}x\in \mathbb {R}^3, \\ -\Delta \phi =K(x)u^2, &{}x\in \mathbb {R}^3, \end{array} \right. \end{aligned}$$\end{document}where a, b are positive constants, and 3<p<5\documentclass[12pt]{minimal}\usepackage{amsmath}\usepackage{wasysym}\usepackage{amsfonts}\usepackage{amssymb}\usepackage{amsbsy}\usepackage{mathrsfs}\usepackage{upgreek}\setlength{\oddsidemargin}{-69pt}\begin{document}$$3<p<5$$\end{document}. Under some proper assumptions on the potentials V, K and h, not requiring nonnegative property, we find a ground state solution for the above problem with the help of Nehari manifold.

Journal

Bulletin of the Malaysian Mathematical Sciences SocietySpringer Journals

Published: Jan 6, 2021

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