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SupposeX is ans-uniformly smooth Banach space (s > 1). LetT: X → X be a Lipschitzian and strongly accretive map with constantk ɛ (0, 1) and Lipschitz constantL. DefineS: X → X bySx=f−Tx+x. For arbitraryx 0 ɛ X, the sequence {xn} n=1 ∞ is defined byx n+1=(1−α n)xn+α nSyn,y n=(1−Β n)xn+Β nSxn,n⩾0, where {αn} n=0 ∞ , {Βn} n=0 ∞ are two real sequences satisfying: (i) 0⩽α n p−1 ⩽ 2−1s(k+kΒ n−L 2Βn)(w+h)−1 for eachn, (ii) 0⩽Β n p−1 ⩽ min{k/L2, sk/(Ω+h)} for eachn, (iii) ⌆n αn=∞, wherew=b(1+L)s andb is the constant appearing in a characteristic inequality ofX, h=max{1, s(s-l)/2},p=min {2, s}. Then {xn} n=1 ∞ converges strongly to the unique solution ofTx=f. Moreover, ifp=2, α n=2−1s(k +kΒ−L2Β)(w+h)−1, andΒ n=Β for eachn and some 0 ⩽Β ⩽ min {k/L2, sk/(w + h)}, then ∥xn + 1−q∥ ⩽ρ n/s∥x1-q∥, whereq denotes the solution ofTx=f andρ=(1 − 4−1s2(k +kΒ − L 2Β)2(w + h)−1 ɛ (0, 1). A related result deals with the iterative approximation of Lipschitz strongly pseudocontractive maps inX. SupposeX ism-uniformly convex Banach spaces (m > 1) andc is the constant appearing in a characteristic inequality ofX, two similar results are showed in the cases of L satisfying (1 − c2)(1 + L)m < 1 + c − cm(l − k) or (1 − c2)Lm < 1 + c − cm(1 − s).
Acta Applicandae Mathematicae – Springer Journals
Published: Jan 3, 2005
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